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Last updated on October 8, 2025

Derivative of (x-2)^2

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We use the derivative of (x-2)^2, which is 2(x-2), to understand how the function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now discuss the derivative of (x-2)^2 in detail.

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What is the Derivative of (x-2)^2?

We now understand the derivative of (x-2)2. It is commonly represented as d/dx ((x-2)2) or ((x-2)2)', and its value is 2(x-2). The function (x-2)2 has a clearly defined derivative, indicating it is differentiable across its domain.

 

The key concepts are mentioned below:

 

Polynomial Function: A standard form of algebraic expression, such as (x-2)2.

 

Power Rule: A basic rule for differentiating polynomial functions.

 

Derivative: Represents the rate of change of a function.

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Derivative of (x-2)^2 Formula

The derivative of (x-2)2 can be denoted as d/dx ((x-2)2) or ((x-2)2)'.

 

The formula we use to differentiate (x-2)2 is: d/dx ((x-2)2) = 2(x-2)

 

The formula applies to all x.

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Proofs of the Derivative of (x-2)^2

We can derive the derivative of (x-2)2 using proofs. To show this, we will use basic differentiation rules.

 

There are several methods we use to prove this, such as:

 

  • By First Principle
     
  • Using Power Rule
     
  • Using Expansion

 

We will now demonstrate that the differentiation of (x-2)2 results in 2(x-2) using the above-mentioned methods:

 

By First Principle

 

The derivative of (x-2)2 can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of (x-2)2 using the first principle, we will consider f(x) = (x-2)2. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = (x-2)2, we write f(x + h) = (x + h - 2)2. Substituting these into equation (1), f'(x) = limₕ→₀ [(x + h - 2)2 - (x-2)2] / h = limₕ→₀ [(x + h - 2)(x + h - 2) - (x-2)(x-2)] / h = limₕ→₀ [x2 + 2xh + h2 - 4x - 4h + 4 - (x2 - 4x + 4)] / h = limₕ→₀ [2xh + h2 - 4h] / h = limₕ→₀ [h(2x + h - 4)] / h Cancel h and take the limit as h approaches 0, f'(x) = 2x - 4 Thus, f'(x) = 2(x-2). Hence, proved.

 

Using Power Rule

 

To prove the differentiation of (x-2)2 using the power rule, We use the formula: d/dx [un] = n * u(n-1) * du/dx Consider u = (x-2) and n = 2 Then, d/dx ((x-2)2) = 2 * (x-2)(2-1) * d/dx(x-2) = 2(x-2) * 1 = 2(x-2)

 

Using Expansion

 

We will now prove the derivative of (x-2)2 using expansion. The step-by-step process is demonstrated below: Expand (x-2)2 to get x2 - 4x + 4. Differentiate each term separately: d/dx(x2) = 2x d/dx(-4x) = -4 d/dx(4) = 0 Combine the derivatives: f'(x) = 2x - 4 Thus: f'(x) = 2(x-2).

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Higher-Order Derivatives of (x-2)^2

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like (x-2)2.

 

For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.

 

For the nth Derivative of (x-2)2, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).

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Special Cases:

For any constant shift in x, the derivative of (x-2)2 is simply recalculated using the same formula, resulting in 2(x-2).

 

At x = 2, the derivative of (x-2)2 = 2(2-2) = 0, indicating a horizontal tangent at this point.

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Common Mistakes and How to Avoid Them in Derivatives of (x-2)^2

Students frequently make mistakes when differentiating (x-2)2. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not simplifying the equation

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Students may forget to simplify the equation, which can lead to incomplete or incorrect results. They often skip steps and directly arrive at the result, especially when solving using different methods.

 

Ensure that each step is written in order. Students might think it is awkward, but it is important to avoid errors in the process.

Mistake 2

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Forgetting the Constant Term

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They might not remember to differentiate the constant term when expanding and then differentiating.

 

Keep in mind the differentiation of constants results in zero, and this should be considered when simplifying the result.

Mistake 3

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Incorrect use of Power Rule

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While differentiating expressions such as (x-2)2, students may misapply the power rule. For example, incorrectly writing d/dx ((x-2)2) = 2(x-2). Remember to apply the chain rule properly, considering the inner function derivative.

 

To avoid this mistake, write the power rule correctly and ensure the chain rule is applied. Always check for errors in calculation and simplify properly.

Mistake 4

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Not writing Constants and Coefficients

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There is a common mistake where students at times forget to multiply the constants placed before the function. For example, they incorrectly write d/dx (5(x-2)2) = 2(x-2).

 

Students should check the constants in the terms and ensure they are multiplied properly. For example, the correct equation is d/dx (5(x-2)2) = 5 * 2(x-2).

Mistake 5

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Not Applying the Chain Rule

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Students often forget to use the chain rule. This happens when the derivative of the inner function is not considered.

 

For example, incorrect: d/dx ((x-2)2) = 2(x-2). To fix this error, students should differentiate the inner function (x-2) and multiply it accordingly.

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Examples Using the Derivative of (x-2)^2

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Problem 1

Calculate the derivative of ((x-2)^2 * (x+3)).

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Here, we have f(x) = (x-2)2 * (x+3). Using the product rule, f'(x) = u′v + uv′ In the given equation, u = (x-2)2 and v = (x+3). Let’s differentiate each term, u′= d/dx ((x-2)2) = 2(x-2) v′= d/dx (x+3) = 1 Substituting them into the given equation, f'(x) = (2(x-2)) * (x+3) + ((x-2)2) * 1 Let’s simplify terms to get the final answer, f'(x) = 2(x-2)(x+3) + (x-2)2 Thus, the derivative of the specified function is 2(x-2)(x+3) + (x-2)2.

Explanation

We find the derivative of the given function by dividing the function into two parts.

The first step is finding its derivative and then combining them using the product rule to get the final result.

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Problem 2

A garden path is represented by the function y = (x-2)^2 where y represents the width of the path at a distance x. If x = 5 meters, measure the width of the path's rate of change.

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We have y = (x-2)2 (width of the path)...(1) Now, we will differentiate the equation (1) Take the derivative: dy/dx = 2(x-2) Given x = 5 (substitute this into the derivative) dy/dx = 2(5-2) dy/dx = 2 * 3 = 6 Hence, we get the rate of change of the width of the path at a distance x = 5 as 6.

Explanation

We find the rate of change of the width of the path at x = 5 as 6, which means that at a given point, the width of the path increases at a rate of 6 units per unit increase of x.

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Problem 3

Derive the second derivative of the function y = (x-2)^2.

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The first step is to find the first derivative, dy/dx = 2(x-2)...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [2(x-2)] = 2 * d/dx(x-2) = 2 * 1 Therefore, the second derivative of the function y = (x-2)2 is 2.

Explanation

We use a step-by-step process, where we start with the first derivative.

By differentiating the linear term within the expression, we find that the second derivative is constant.

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Problem 4

Prove: d/dx ((2x-4)^2) = 4(2x-4).

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Let’s start using the chain rule: Consider y = (2x-4)2 To differentiate, we use the chain rule: dy/dx = 2 * (2x-4) * d/dx (2x-4) Since the derivative of (2x-4) is 2, dy/dx = 2 * (2x-4) * 2 dy/dx = 4(2x-4) Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation.

We replace the inner function with its derivative.

As a final step, we simplify to derive the equation.

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Problem 5

Solve: d/dx ((x-2)^2/x).

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To differentiate the function, we use the quotient rule: d/dx ((x-2)2/x) = (d/dx ((x-2)2) * x - (x-2)2 * d/dx(x))/x² We will substitute d/dx ((x-2)2) = 2(x-2) and d/dx(x) = 1 = (2(x-2) * x - (x-2)2 * 1) / x² = (2x(x-2) - (x-2)2) / x² = (2x(x-2) - (x2 - 4x + 4)) / x² = (2x2 - 4x - x2 + 4x - 4) / x² = (x^2 - 4) / x² Therefore, d/dx ((x-2)2/x) = (x2 - 4) / x²

Explanation

In this process, we differentiate the given function using the product rule and quotient rule.

As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of (x-2)^2

1.Find the derivative of (x-2)^2.

Using the power rule, d/dx ((x-2)^2) = 2(x-2)

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2.Can we use the derivative of (x-2)^2 in real life?

Yes, we can use the derivative of (x-2)^2 in real life in calculating rates of change in various situations, such as physics problems or optimization in economics.

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3.Is it possible to take the derivative of (x-2)^2 at any point?

Yes, (x-2)^2 is a polynomial function, which means it is differentiable at all points on the real number line.

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4.What rule is used to differentiate (x-2)^2/x?

We use the quotient rule to differentiate (x-2)^2/x, d/dx ((x-2)^2/x) = (x * 2(x-2) - (x-2)^2 * 1) / x².

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5.Are the derivatives of (x-2)^2 and 2(x-2) the same?

No, they are different. The derivative of (x-2)^2 is 2(x-2), whereas 2(x-2) is not a derivative but the result of differentiating (x-2)^2.

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Important Glossaries for the Derivative of (x-2)^2

  • Derivative: A measure of how a function changes as its input changes.

 

  • Polynomial Function: An algebraic expression consisting of variables and coefficients.

 

  • Power Rule: A rule in calculus for differentiating expressions of the form xn.

 

  • First Principle: A method of finding the derivative based on limits.

 

  • Chain Rule: A formula for computing the derivative of the composition of two or more functions.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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